The number of optically active stereoisomers possible for 2,3−diol is 2. They are d,l isomers which are optically active. The meso- compound is optically inactive due to internal compensation. Hence, option B is correct. We know from the formula that these isomers contain no rings or double bonds. The isomers must be alcohols and ethers. Lets' start by drawing the alcohols. Start with four carbons in a row and put an O H group in every possible position. This gives us 1. C H 3 C H 2 C H 2 C H 2 O H , butan 1-ol and 2. C H 3 C H 2 C H (O H) C H 3, butan-2-ol Now use a 3 - carbon chain with a C H 3 on the middle carbon. This gives (C H 3) 2 C H C H 2 O H, 2-methylpropane -1-ol and (C H 3) 3 C O H, 2 ... Shiva asked surabhi to draw the structural isomers of pentane. How many structural isomers possibly she can make? There are five constitutional isomers with the formula C4H 8. They are But-1-ene But-2-ene 2-Methylpropane Cyclobutane methylcyclopropane Hence, this is the answer.
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